输入一行字符，统计其中有多少个单词，单词之间用空格分隔开

#include<stdio.h>

int main()
{
	char str[81];
	int number=0, i, word=0;

	gets(str);
	
	for(i=0;(str[i])!='\0';i++)

		if(str[i]=="")  word=0;
		else if(word==0)
		{
			word = 1;
			number += 1;
		}

	printf("%d", number);

	return 0;
}

程序报错如下：
1.error C2446: '’ : no conversion from ‘char *’ to ‘int’ This conversion requires a reinterpret_cast, a C-style cast or function-style cast
2.error C2040: '’ : ‘int’ differs in levels of indirection from ‘char [1]’

检查错误发现，单个字符应该是单引号，而不能用双引号。

#include<stdio.h>

int main()
{
	char str[81];
	int number=0, i, word=0;

	gets(str);
	
	for(i=0;(str[i])!='\0';i++)
		if(str[i]==' ')  word=0;
		else if(word==0)
		{
			word = 1;
			number += 1;
		}

	printf("%d", number);
	return 0;
}

结果为：